-64x^2+12=-4

Solution for -64x^2+12=-4 equation:

-64x^2+12=-4

We move all terms to the left:

-64x^2+12-(-4)=0

We add all the numbers together, and all the variables

-64x^2+16=0

a = -64; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·(-64)·16
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64}{2*-64}=\frac{-64}{-128}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64}{2*-64}=\frac{64}{-128}
=-1/2
$